3/2x^2-8=16

Solution for 3/2x^2-8=16 equation:

3/2x^2-8=16

We move all terms to the left:

3/2x^2-8-(16)=0


Domain of the equation: 2x^2!=0

x^2!=0/2

x^2!=√0

x!=0

x∈R


We add all the numbers together, and all the variables

3/2x^2-24=0

We multiply all the terms by the denominator


-24*2x^2+3=0

Wy multiply elements

-48x^2+3=0

a = -48; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-48)·3
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-48}=\frac{-24}{-96}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-48}=\frac{24}{-96}
=-1/4
$